Answer :

Let 1, 2, 3, 4 denote the event 1, 2, 3, 4 numbered slip is drawn

When two slips are drawn without replacement the first event has 4 possible outcomes and the second event has 3 possible outcomes

So the total number of possible outcomes=(4×3)=12

We define the possible outcomes by an ordered event (x , y)

x denotes the first event the first slip is drawn

y denotes the second event the second slip is drawn

The sample space S={(1,2),(1,3),(1,4),(2,1),(2,3),(2,4),(3,1),(3,2),(3,4),(4,1),(4,2),(4,3)}

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